Question

. A box has 4 red balls and 12 black balls. the probability that the selected ball is (i) a red ball (ii) a black ball ​

Answer 1

$1) \: probability(red \: ball) \: = \frac{4}{16}$

$2) \: probability(black \: ball) = \frac{12}{16}$

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Answer 2

NUMBER OF RED BALLS = 4

NUMBER OF BLACK BALLS = 12

TOTAL BALLS = 12+4 = 16

i) PROBABILITY = NUMBER OF FAVOURABLE OUTCOMES / TOTAL OUTCOMES

PROBABILITY = 4/12

= 1/3

HENCE THE PROBABILITY OF GETTING A RED BALL IS 1/3.

ii) PROBABILITY = 12/16

= 3/4

HENCE THE PROBABILITY OF GETTING A BLACK BALL IS 3/4.

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