Question

If the side of a rhombus is 10 cm and one diagonal is 16 cm, then the area of the rhombus is?

Answer 1

Let the length of each side of a rhombus is x cm and the length of diagonals are

d1 and d2 cm. respectively. Accordingly :-

x=10 cm. , d1= 16 cm. , d2 = ?

(d1/2)^2 + (d2/2)^2= x^2.

or, (16/2)^2+(d2/2)^2 = (10)^2.

or, (d2/2)^2 =100–64 = 36.

or, d2/2 = √36 = 6.

or, d2 = 12 cm.

Area of rhombus = (d1×d2)/2 = (16×12)/2 = 96 cm^2. Answer.

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Answer 2

Answer:

Step-by-step explanation:

Diagonal=16cm

Side=10 cm

Area of rhombus =1/2(d1)(d2)

D2= side^2 - ( D1)^2

D2= (10)^2-(8)^2

D2= 12 cm

Area = 1/2 (12)(16)

Area =96 cm^2