a box of 600 electric bulbs contains 12 defective bulbs one bulb is taken out at random from this box .what is probality that it is a non defective bulf?
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2
hlo mate.....
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Sol: Out of 600 electric bulbs one bulb can be chosen in 600 ways ⇒Total number of outcomes = 600 Number of non-defective bulbs = 600 -12 = 588 ⇒ Number of favourable outcomes = 588P(Getting a non-defective bulb) = ⇒ Probability 588/600
Hence, the probability of getting a non-defective bulb = 0.98
hope it helps u ...
brainliest pls
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Sol: Out of 600 electric bulbs one bulb can be chosen in 600 ways ⇒Total number of outcomes = 600 Number of non-defective bulbs = 600 -12 = 588 ⇒ Number of favourable outcomes = 588P(Getting a non-defective bulb) = ⇒ Probability 588/600
Hence, the probability of getting a non-defective bulb = 0.98
hope it helps u ...
brainliest pls
harshalmane:
its wrong
Answered by
3
hey mate!!
here is your answer:
total number of outcomes=600
number of favourable outcomes=600-12=588
probability of non defective bulbs=588/600=49/50
hope it helped!!
here is your answer:
total number of outcomes=600
number of favourable outcomes=600-12=588
probability of non defective bulbs=588/600=49/50
hope it helped!!
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