Physics, asked by mohammeddemachkie, 9 months ago

A box weighing 360 N rests on the ground. The bottom of the box measures 0.30 m
by 0.20 m. How much pressure does the box exert on the ground?

Answers

Answered by shraddhazutshi312
3

Answer:

pressure =force/area

pressure = 360/lxb

pressured =360/0.30x0.20

pressure =60,000Pa or N/m^2

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Answered by bhuvna789456
0

Pressure exerted by the box on ground is 6000 Pa ( N m²) or 6 k Pa

Explanation:

  • Pressure is defined as the quantity given by the ratio of force or particularly weight of the body (lying on the surface) to area of the given surface on which the is placed

                   Pressure = \frac{Force}{Area}

  • SI unit of pressure is pascal (Pa) or Newton- meter² (N-m²), it is a scalar quantity that is have only direction and do not possess any direction
  • Pressure depends inversely to the area of contact that is small area exerts more pressure or vice-versa

Given, Weight of body = 360 N

Force = weight of the body = 360 N

Bottom has measure = 0.30 *0.20

length = 0.30 m

breadth = 0.20 m

Area = length * breadth

=> Area = 0.30 *0.20

=> Area = 0.06 m²

                   Pressure = \frac{Force}{Area}

=> Pressure = \frac{360}{0.06}

=> Pressure = 6000 Pa

=> Pressure = 6 k Pa

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