A boy gets 3 marks for each correct answer and Loses 2 marks for each incorrect Sum. He does 24 sums and obtains 37 marks. what is the total number of Correct sums?
Answers
Answered by
378
Let the total number of correct sums = x.
Then the total number of incorrect sums =24 - x.
Given that he gets 3 marks for each correct answer and loses 2 marks for each incorrect sum. and he obtained 37 marks.
3x - (24 - x) * 2 = 37
3x - 48 + 2x = 37
5x - 48 = 37
5x = 37 + 48
5x = 85
x = 85/5
x = 17.
Therefore the number of correct sums = 17.
Hope this helps!
Then the total number of incorrect sums =24 - x.
Given that he gets 3 marks for each correct answer and loses 2 marks for each incorrect sum. and he obtained 37 marks.
3x - (24 - x) * 2 = 37
3x - 48 + 2x = 37
5x - 48 = 37
5x = 37 + 48
5x = 85
x = 85/5
x = 17.
Therefore the number of correct sums = 17.
Hope this helps!
siddhartharao77:
Thanks for the brainliest abi
Answered by
124
hey friend here is your answer.
Attachments:
Similar questions