A boy has 4 different boxes and 5 different marbles. In how many ways can he place the marbles in the boxes such that each box has at least one marble ?
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Answered by
21
Boxes 4 different marbles 5 different
(A,B,C,D) (1,2,3,4,5)
Each box needs to get one marble at least. The number of ways of arranging four marbles of 5 in four boxes = 5P4 = 5!.
Then the 5th marble can be placed in any of the 4 boxes.
So total number of ways = 5! * 4 = 480
(A,B,C,D) (1,2,3,4,5)
Each box needs to get one marble at least. The number of ways of arranging four marbles of 5 in four boxes = 5P4 = 5!.
Then the 5th marble can be placed in any of the 4 boxes.
So total number of ways = 5! * 4 = 480
Answered by
20
Let the boxes be b 1, b 2, b 3 and b 4
so,
box 1 can be filled in ways = 5
box 2 can be filled in ways = 4
box 3 can be filled in ways = 3
box 4 can be filled in ways = 2
so, 5*4*3*2 = 120 ways
Lastly any of 4 can be filled with 5th marble in 4 ways.
So, 120*4 = 480 ways Answer
so,
box 1 can be filled in ways = 5
box 2 can be filled in ways = 4
box 3 can be filled in ways = 3
box 4 can be filled in ways = 2
so, 5*4*3*2 = 120 ways
Lastly any of 4 can be filled with 5th marble in 4 ways.
So, 120*4 = 480 ways Answer
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