A boy has x coins of 50 paise each,2x coins of 25paise each, 4x coins of 10 paise each and 8x coins of 5paise each. Find the number of paise coins, if the value of all the coins is rupees 9
Answers
180x=900
x=900/180
x=5
no. of 50 paise coins=5
no. of 25 paise coins=2×5=10
no. of 10 paise coins=4×5=20
no. of 5 paise coins=8×5=40
total no. of coins=75
Answer:
Step-by-step explanation:-
Given;
Sum of all coins = Rs.9 =900paise.
So;
Total value of 50 paise coins = 50×x =50x.
Total value of 25 paise coins = 25×2x=50x.
Total value of 10 paise coins = 10×4x= 40x.
Total value of 5 paise coins = 5×8x= 40x.
Sum of all coins = 900paise.
50x+50x+40x+40x=900.
180x=900.
Transfer 180 to R.H.S.:-
x=900/180.
x=5.
No.of 50paise coins = x= 5.
No.of 25paise coins =2x = 2×5= 10.
No.of 10paise coins = 4x = 4×5=20.
No.of 5paise coins = 8x = 8×5= 40.
Let's verify our answer:-
Total value of 50paise coins=50x = 50×5=250(2.5rupees).
Total value of 25paise coins=50x=50×5=250(2.5rupees).
Total value of 10paise coins =40x=40×5=200(2 rupees).
Total value of 5paise coins =40x=40×5=200(2 rupees).
Total value of all coins together= 2.5+2.5+2+2.
= 9 rupees.
Hence, our answer is correct.
Hope it helps you.
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