Question

a boy is going from one place to Another. he goes 100m north and then 70m east. find the displacement of the boy from his starting point.

Answer 1

Answer is sent via picture

Answer 2

Concept:

A displacement is a vector whose length is the shortest distance from the initial to the final position of an object or point in motion.

Given:

The boy travels $100m$ north and then $70m$ east.

Find:

The displacement of the boy from his starting point.

Solution:

The boy first travels $100m$ north and then $70m$ east from there.

North means positive $y$ axis, so $10j$.

East means positive $x$ axis, so $7i$.

Now, displacement is the shortest path, therefore it will form a right-angled triangle. Where hypotenuse is the displacement.

Using Pythagoras theorem,

$displacement=\sqrt{100^2+(70)^2} \\displacement=\sqrt{149000}=122.065m$

The displacement of the boy from his starting point is $122.065m$.

#SPJ2