In a labooratory , the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if it count was initially 506000.
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Since it is 2.5% per hr, for two hrs it would be 5% increase.
Hence the increase=(5/100)x506000= 25300.
Therefore the total number of bacteria=506000+25300
=531300.
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