A boy of mass 50 kg running 5m/s jumps on to a 20 kg trolley travelling in the same direction at 1.5 m/s .find their common velocity
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Hello,
Please refer to the above photo for the used process
The answer is 4 m/sec
We have used the concept of the law of conservation of momentum.
Hope this will be helping you
Please refer to the above photo for the used process
The answer is 4 m/sec
We have used the concept of the law of conservation of momentum.
Hope this will be helping you
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Answered by
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Mass of boy = m1 = 50 kg
Mass of trolley = m2 = 20 kg
Initial velocity of boy = u1 = 5 ms-1
Initial velocity of trolley = u2 = 1.5 ms-1
Final velocity =
v = m1u1 + m2u2 \ m1 + m2
50 × 5 + 20 × 1.5 ÷ 50 + 20
= 4ms-1
HOPE IT HELPS YOU!!!
Mass of trolley = m2 = 20 kg
Initial velocity of boy = u1 = 5 ms-1
Initial velocity of trolley = u2 = 1.5 ms-1
Final velocity =
v = m1u1 + m2u2 \ m1 + m2
50 × 5 + 20 × 1.5 ÷ 50 + 20
= 4ms-1
HOPE IT HELPS YOU!!!
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