A boy of mass 50 kg running at 5m/s jumps on to a 20 kg trolley travelling in the same direction at 1.5 m/s. what is their common velocity?
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the answer is ( 3/4. )
eshitastteresa:
can i get the proper solution??
pls. mark a brainly
the 50×5=100,,,20×1.5=75 then 100/75 = 4/3
thanks
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Answered by
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Mass of boy = m1 = 50 kg
Mass of trolley = m2 = 20 kg
Initial velocity of boy = u1 = 5 ms-1
Initial velocity of trolley = u2 = 1.5 ms-1
Final velocity =
v = m1u1 + m2u2 \ m1 + m2
50 × 5 + 20 × 1.5 ÷ 50 + 20
= 4ms-1
HOPE IT HELPS YOU!!!
Mass of trolley = m2 = 20 kg
Initial velocity of boy = u1 = 5 ms-1
Initial velocity of trolley = u2 = 1.5 ms-1
Final velocity =
v = m1u1 + m2u2 \ m1 + m2
50 × 5 + 20 × 1.5 ÷ 50 + 20
= 4ms-1
HOPE IT HELPS YOU!!!
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