Question

a boy read 3/8th of the book on one day and 4/5th of the remainder on another day. If there were 30 pages unread, how many pages did the book contain?


answer should come 240 pages​

Answer 1

➡️ Hunar,

If $3/8$ of the book were read the first day, then $5/8$ remained.

$4/5\:of\:5/8 = 4/5 * 5/8 = 4/8$

So now $3/8 + 4/8 = 7/8$ have been read.

The $30$ pages that remain must be 1/8 of the total.

So if p is the total number of pages:

$p/8 = 30$

$p = 240\:pages$

✡️ HOPE IT HELPS YOU...

✡️ GOOD EVENING...

Answer 2

Answer:

imagine, total pages as x

3/8 th of the book was read on the first day.

so, there are 5/8th of the pages left.

on the second day, (4/5)(5/8) = (4/8)

totally, (3/8)+(4/8) = (7/8)th of the pages were completed and (1/8)th of the book is left which is given as 30.

(1/8)(x) = 30

=> x= 240.

so, totally, the book contains 240 pages.

hope this helps you

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