Question

A gaseous mixture containing 80% of N2 at 5 atm pressure is passed through water. Calculate the number of moles of N2 dissolved in 10 moles of water. Given KH of N2 = 4x105atm.

Answer 1

Explanation:

Total pressure is 5 atm. The mole fraction of nitrogen is 0.8.

Hence,the partial pressure of nitrogen=P

T

×X=0.8×5=4 atm

According to Henry's law, P=KX

x is the mole fraction

K is the henry's law constant

P is the pressure in atm.

Substitute values in the above expression.

X=

1×10

5

atm

4 atm

=4×10

−5

=

10

n

n=4.0×10

−4

mol

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