Question

A boy standing in front of a wall at a distance of 85m produces 2 claps per second. He notices that the sound of his clapping coincides with the echo. The echo is heard only once when the clapping is stopped calculate the speed of sound.​

Answer 1

Answer:

Here, distance of the boy from the wall,

<br> time taken by the echo to be heard,

<br> If

is distance between the boy and the wall, total distance travelled by sound in going and coming back

<br> As distance travelled by sound = speed of sound xx time, <br>

or

.

Explanation:

hope it helps you..

Answer 2

Answer:

In one second two claps are produced

so time interval t=12=0.5

Distance between wall and boy d =85cm

speed of sound v= 2dt

2d is because sound travel once from boy to wall and then

again wall to back.

v=2×850.5

=340m/s