a boy standing on a cliff drops a ball. what will be the velocity of the ball after 10 sec before it reaches the ground?
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Answer:
velocity of ball will be 98 m/s
Explanation:
u = o m/s , v = ? , a = g
by 1st equation of motion
v = u + at
v = 0 + 9.8(10)
v = 98 m/s
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