Question

A boy stands 60 m in front of a tall wall and claps. The boy continues to clap
every time an echo is heard. Another boy finds that the time taken between
the first and fifty-first clap is 18 s. Calculate the speed of sound.​

Answer 1

Answer:

PLZZ me a brain list

Explanation:

The boy claps only when he hears an echo. Hence the time taken here is the time between successive claps and during this time interval, the wave travels a distance of 120m. Since the time taken between the first and the 51st clap is 18s, time interval between any two claps is 18/(51-1) =0.36secs

The velocity of the sound wave is V=120/0.36 = 333.33 m/

Answer 2

Answer:

• 333 m/s

Explanation:

Given

• Distance of boy from the wall = 60 m
• Time interval between 1st and 51st clap = 18 s

To find

• Speed of sound

Solution

→ Total distance travelled by boy = 2d (since echo)

• 2(60)
• 120 m

→ Time interval between 1st and 51st clap = 18 s

∴ Time taken between two successive claps = 18/50 s

or time taken to hear the echo = 18/50 s

Now,

• Speed of sound = Total distance/Time taken
• v = 2d/t

Substituting we get,

• 120 m/(18/50) s
• 333 m/s

Hence, the speed of sound is 333 m/s.