Question

A brick with dimensions 20 cm x 10 cm x 5 cm has a weight 500 gwt. Calculate the
pressures exerted by it when it rests on different faces ?

Answer 1

P1 = 0.01 Pa

P2 = 0.0025 Pa

P3 = 0.005 Pa

Explanation:

given - lxbxh = 20×10×5 and F = 500 gm.wt.

solution :

A1 = lxb = 20 x 10 = 200 cm²

A2 = bxh = 10 x 5 = 50 cm²

A3 = lxh = 20x5 = 100 cm²

we know

P = F /A

therfore

P1 = F/A1 = 500/200 = 2.5 dyne/cm²

P2 = F/A2 = 500/50 = 10 dyne/cm²

P3 = F/A3 = 500/100 = 5 dyne/cm²

if you want in N/m²(pascal) then multiply P by 10^(-1)