Question

⦁ A bronze statue weighs 2400 N and has a base that is 4 m by ½ m. What is the pressure the statue exerts on the floor?

Answer 1

Here,

$Weight = 2400 \:$

$Dimension \: \: of \: \: Base = 4 \: m \times \frac{1}{2} \: m$

• To find : Pressure exerted by the statue on the floor

So,

$\text{Area of the base} = 4 \times \frac{1}{2} = 2 \: \rm \: {m}^{2}$

Thus,

$Pressure = \frac{force}{area} \\ \\ = > \frac{2400}{2} = \pink{1200 \: \rm{}pa}$

Hence,

• The Statue exerts a pressure of 1200 Pascals on floor.