Question

A builder decided to build a farmhouse in 20 days. He employed 40 men in the beginning and 20 more after 10 days and completed the construction in stipulated time. If he had not employed the additional men, how many days behind schedule would it have been finished?

Answer 1

Answer:

5 days behind the schedule they would have finished the work.

Step-by-step explanation:

Here's the solution to the problem:

Total men working in this project of farmhouse are 60men.In the starting only 40men were there and after 10 days 2O more men were employed to finish the work in 20 days duration.

Total men= 40+20=60 men.

60men doing the rest of the work in 20-10= 10 days.

When 40 men doing the remaining of the work=(10*60)/40=15 days.

So, according to the above question if the additional number of employees were not employed then the work would have lasted 15-10=5 days longer.

Answer 2

Final Answer:

The number of days behind the schedule the building of the farmhouse would have been finished if he had not employed the additional men, is 5 days.

Given:

A builder decided to complete the task of building a farmhouse in 20 days.

He employed 40 men in the beginning and 20 more men after 10 days and completed the construction in the stipulated time.

To Find:

The number of days behind the schedule the building of the farmhouse would have been finished if he had not employed the additional men, is to be calculated.

Explanation:

The concept of the unitary method can be employed to arrive at the solution to the present problem.

The unitary method employs the per-unit value obtained from the given data to find the respective value of the unknown quantity.

Step 1 of 3

As per the information given in the problem, write the following.

• The total time taken to complete the farmhouse is 20 days.
• The number of men who worked for the first 10 days is 40 men.
• The number of men who worked for the last 10 days is

$=40+20\\=60\; men$

Step 2 of 3

Using the above information in the given problem, the following can be observed.

• The number of days in which 60 men complete a piece of work is 10.
• So, the number of days in which 1 man completes the same piece of work is $=10\times 60$

Step 3 of 3

In continuation with the above calculations, the number of days in which 40 men can complete the same piece of work is

$=\frac{10\times 60}{40}\\=15$

So, the number of days behind schedule when it would have been finished is

$=(10+15)-20\\=25-20\\=5\; days$

Therefore, the required number of days behind the schedule is 5 days.

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