a bulb is rated at 200v-40w what is resistance 5 such bulb are lighted for 5 hours calculate the electrical energy consumed find the cost if the rate is ₹5.10 per KWh
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V= 200V
P=40W
P=V^2/R
R=V^2/P
=200×200/40= 1000ohm
TOT P=5×40=200W =0.2kW
E=0.2×5=1kWh
Cost=Rs5.10
P=40W
P=V^2/R
R=V^2/P
=200×200/40= 1000ohm
TOT P=5×40=200W =0.2kW
E=0.2×5=1kWh
Cost=Rs5.10
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