A bulb withdraws 300 Coulomb charge for half an hour? How much current is required by the bulb? Also find the work done to move 300 Coulomb charge when a 12 volt battery is used in the circuit?
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Answer:Q=300c
Time=1/2hrs=30min
Current(I)=Q/T
= 300/30
=10A......answer
Q=300c
P.d=12v
W=p.d ×q
=12×300
=3600......answer
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