Physics, asked by sanjanaaveesam4700, 1 year ago

A bullect with the speed 150m/s penetrates 3.2cm what is the retardation

Answers

Answered by ShuchiRecites
0
\textbf{ \underline{ Hello Mate! }}

Initial speed ( u ) = 150 m/s

Final speed ( v ) = 0

Distance of penetration = 3.2 cm

Converting it into m we get 0.032 m

 {v}^{2}  -  {u}^{2}  = 2as \\ 0 -  {(150)}^{2}  = 2a(0.032) \\  - 22500 = 0.064a \\  - 351,562.5 = a
But if you mean by 3.2 m and not cm then

0 -  {(150)}^{2}  = 2a(3.2) \\  - 22500 = 6.4a \\  - 3,515.625 = a

\textbf{ Have great future ahead! }
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