Question

a bullet accelerates at the rate of 90,000ms^-2 from rest. Calclate its velocity if it travels a distence of 0.5 m while accelerating.

Answer 1

Answer:

300 m/s

Explanation:

Given that,

a=90000 m/s^2

s=0.5m

and we know u=0

we have to find v

so applying equation of motion,

v^2-u^2=2as

v^2-0=2×0.5×90000

v^2=90000

v=√90000

v=300 m/s

hope this helps...mark it as my first brainliest answer.Thank you