Question

A bullet hits a wall with a velocity of 20 m/ s and penertrates it up to distance of 5 cm . find the deacceleration of the bullet in the wall ..

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Answer 1

hoi mate hers your answer

u= 20 m/s

v= 0

s = 5 cm = 0.05 m

v² -u² = 2as

⇒0 - (20)² = 2×0.05×a

⇒0.1 a = - 400

⇒a = - 4000 m/s²

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