a bullet is fired on a wall with a velocity of 100 M second if the Bullet stops at a depth of the 10cm inside the wall then find the retardation produced by the walk
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һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
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✯▶intial velocity of the bullet = 100 m/ s
▶bullet strike with wall and after 10cm moving in wall bullet will be rest .
i.e.final velocity = 0
then ,we can use kinematic equation,


(10cm = 10 / 100 m)

=》

hence , retardation produced by the walk is,


✪ BRAINLY✪
հίί ʍαtε_______✯◡✯
.
.
.
.
_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯▶intial velocity of the bullet = 100 m/ s
▶bullet strike with wall and after 10cm moving in wall bullet will be rest .
i.e.final velocity = 0
then ,we can use kinematic equation,
(10cm = 10 / 100 m)
=》
hence , retardation produced by the walk is,
✪ BRAINLY✪
ArohiG:
Hello Gaurav
Answered by
15
Initial velocity of bullet = 100m/s
Bullet strike with wall and after 10cm moving in wall bullet will be rest .
e.g final velocity = 0
use kinematic equation ,
V² = u² + 2aS
0 = 100² + 2a× 10/100
[ 10 cm = 10/100 m ]
-10000 =( 20/100)× a
a = -50000 m/s²
hence,
Retardation produced by wall = -50000 m/s²
Hope it helps to you.
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