A bullet moving with velocity v collides against wall consequently half of its kinetic energy is converted into heat if the whole heat is acquired by the bullet the rise in temp
Answers
Answered by
74
Enegry of the bullet when bullet hits the
wall= 1/2 mv²
Heat energy = Energy / 2 =1/4mv²
Heat energy = ms∆T
where T is change in temperature
=>ms∆T=1/4mv²
=>∆T=v²/4s
wall= 1/2 mv²
Heat energy = Energy / 2 =1/4mv²
Heat energy = ms∆T
where T is change in temperature
=>ms∆T=1/4mv²
=>∆T=v²/4s
Answered by
7
Answer:
v^2/4js
Explanation:
w=JQ,j=mechanical equivalent of heat
1/4mv^2=ms del T
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