A bulet of mass 5g is moving with spesd 400ms strike a target then calculate rise of temperature of bullet assuming all lose of kinetic energy is converted into heat energy of bullet
Answers
Answered by
4
K.E. = 1/2mv^2
= 1/2 * 5/1000 * 160000
= 400 J
1899.1005J = 1 celcius heat unit
400J = 0.21 celcius heat unit
Hope this helps.... plsss make it the brainliest
= 1/2 * 5/1000 * 160000
= 400 J
1899.1005J = 1 celcius heat unit
400J = 0.21 celcius heat unit
Hope this helps.... plsss make it the brainliest
Answered by
13
Answer:160 °C
Explanation:
K.E. of bullet = mv^2/2 = 5/1000*400*400*1/2 = 400J
mcdt = K.E
5/1000*500*dt = 400
dt = 160°C
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