Question

A bullet of mass 10 g is fired from a rifle. The bullet takes 0.003 \(s\) to move through its barrel and leaves with a velocity of 300 \(ms^{-1}\). What is the force exerted on the bullet by the rifle?

Answer 1

Answer:

The force is

=

1000

N

Explanation:

The impulse due to the force is equal to the change in momentum

F

t

=

m

Δ

v

The time is

t

=

0.003

s

The mass of the bullet is

m

=

10

g

=

0.01

k

g

The change in velocity of the bullet is

Δ

v

=

300

m

s

−

1

The force is

F

=

m

Δ

v

t

=

0.01

⋅

300

0.003

=

1000

N

Answer 2

Answer:

1000N

Explanation:

Mass of bullet=10g=0.01kg.Its velocity=300m/s

So its momentum=0.01×300=3N.S.As ∆t for application of force=0.003s=>

Force=momentum/∆t=3/0.003N=1000N.Ans

Hope it helped!!!