Question

A bullet of mass 15 grams moving with the velocity 300m/s in an horizontal direction gets embedded in a freely suspended wooden block of mass 1.2 kg. what is the velocity of the block after the bullet is embedded in it

Answer 1

Answer:

Given:

Bullet mass m: 15g. (0.015 Kg)

Wooden block mass M: 1.2 Kg

velocity of bullet (v): 300ms⁻¹

Velocity (V): ?

We now use this formula of the law of conservation of momentum:

mv =( m+M)V

0.015×300=(0.015+1.2)V

v=4.5/1.215

v=3.7ms⁻¹

HOPE THIS HELPS :D