Question

A bullet of mass 150gms strikes a target at a rate of 600 m/s .Which is reduced to 150 m/s.The loss of energy is

Answer 1

Answer:

So  loss in kinetic energy=25.31 KJ

Explanation:

Given that

mass m = 150  gm  ⇒m= 0.15 Kg

Initial velocity = 600 m/s

Final velocity =150m/s

We know that kinetic energy given as follows

$KE=\dfrac{1}{2}mv^2$

So

initial kinetic energy

$KE_i=\dfrac{1}{2}mv_i^2$

$KE_i=\dfrac{1}{2}\times 0.15\times 600^2$

$KE_i=27 KJ$

Final kinetic energy

$KE_f=\dfrac{1}{2}mv_f^2$

$KE_f=\dfrac{1}{2}\times 0.15\times 150^2$

$KE_f=1.68 KJ$

loss in kinetic energy=27 - 1.68 KJ

So  loss in kinetic energy=25.31 KJ