Question

A bullet of mass 150 gm. Strikes a target at 600 m/s. Velocity which is reduced to 150 m/s. The loss of energy is

Answer 1

Answer:

                The loss of Kinetic energy is 25312.5 Joules.

Explanation:

Given Data:

Mass of bullet (m)=150gm or .15kg

Initial Velocity  (v)=600 m/s

Final Velocity (v1)= 150 m/s

Formula:

          Kinetic Energy =1/2 *mass*velocity^2

So, Initial Kinetic Energy before hitting the target is:

$K.E_{initial} =\frac{1}{2}(0.15*600^2)\\ =\frac{1}{2}(0.15*360000)\\=\frac{1}{2}*54000\\ K.E_{initial}=27000J$

Hence, Final Kinetic Energy after hitting the target would be:

$K.E_{Final} =\frac{1}{2}(0.15*150^2)\\ =\frac{1}{2}(0.15*22500)\\=\frac{1}{2}*3375\\ K.E_{Final}=1687.5J$

           Loss of Kinetic Energy= K.E(intial)-K.E(final)

=27000J-1687.5J

Loss of K.E = 25312.5J

Hope you find it helpful  :)