Question

A cricketer can throw a ball to a maximum horizontal distance of 160 m. Calculate maximum vertical height

Answer 1

Answer:

Explanation:max range is if theta =45

A/Q

R=160=u2sin2theta/g

U2/g=160. Hence u=40

Now

Hmax=2usin theta/g= 80/10 root2

=4 root 2

Answer 2

Answer:

80m

Explanation:

Range = u^2 sin2 theta

160= u^2 sin2theta/g

As it is the maximum distance theta is 45°

160=u^2/g

u=40m

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For whole answer refer pic