A bullet of mass 30g is moving with a velocity of 500 m/s . It penetrates 10 cm in to a
still target and comes to rest ,calculate
1) The kinetic energy possessed by the bullet .
2) The average retarding force offered by the target.
Answers
Answered by
0
Answer:
Kinetic energy = 1/2 × mv²
= 1/2 × 30 × 500²
= 15 × 250000
= 3750000 J
Answered by
1
Answer:
mass of bullet (m)= 30/1000 g =0.003kg
velocity (v)= 500 m/s
initial kinetic energy= 1/2mv²
= 1/2 * 0.02 * (500)²
on solving u will get kinetic energy
final kinetic energy= 1/2mv²=0
loss in K.E= 3750 J
force=?
displacement (S)=10 cm= 0.10m
on application of work energy principle,
W= ∆k
Fs=∆k
F * 10= 3750
so F= 3750/0.10
on solving this u will get force
hope it helps :))
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