Question

A bullet of mass 30g is moving with a velocity of 500 m/s . It penetrates 10 cm in to a

still target and comes to rest ,calculate

1) The kinetic energy possessed by the bullet .

2) The average retarding force offered by the target.​

Answer 1

Answer:

Kinetic energy = 1/2 × mv²

= 1/2 × 30 × 500²

= 15 × 250000

= 3750000 J

Answer 2

Answer:

mass of bullet (m)= 30/1000 g =0.003kg

velocity (v)= 500 m/s

initial kinetic energy= 1/2mv²

= 1/2 * 0.02 * (500)²

on solving u will get kinetic energy

final kinetic energy= 1/2mv²=0

loss in K.E= 3750 J

force=?

displacement (S)=10 cm= 0.10m

on application of work energy principle,

W= ∆k

Fs=∆k

F * 10= 3750

so F= 3750/0.10

on solving this u will get force

hope it helps :))