A bullet of mass 40g is fired from a gun of mass 8Kg with a velocity of 800m/s, calculate recoil velocity of gun
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Answered by
2
Step-by-step explanation:
given m1 = 40 g = 0.040 kg
m2= 8kg
the bullet is moving so the initial velocity will be 0
so u=0
v2 = 800
v1=?
put the above in the formula
(m1+m2) u= m1v1+m2v2
as u is 0 so LHS will be 0
0= 0.040×v1+ 8×800
0= 0.040×v1+6400
-6400=0.040v1
v1=-6400/0.040
=-160000
Answered by
3
Answer:
Step-by-step explanation:given m1 = 40 g = 0.040 kg
m2= 8kg
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