A bullet of mass 50 gram is fired from a gun if the bullet acquires a velocity of 100m/s in 0.1 seconds what is the recoil force on the gun
Answers
Answered by
9
mass(m)=50g=0.050kg=0.05kg
final velocity (v)=100m/s
initial velocity (u)=0
time (t)=0.1s
force(f)=?
acceleration (a)=v-u/t
=100-0/0.1
=1000m/s
thus, force(f)=ma
= 0.05*1000
=50 N
final velocity (v)=100m/s
initial velocity (u)=0
time (t)=0.1s
force(f)=?
acceleration (a)=v-u/t
=100-0/0.1
=1000m/s
thus, force(f)=ma
= 0.05*1000
=50 N
Bebrainly2:
0.005 ----> 0.05
Answered by
7
hello there!!!!
mass of bullet = 50 g = 50 / 1000 kg = 1/20kg
Initial velocity ,ie bullet at rest in the gun
u = 0
and final velocity ,v = 100m/s
t = 0.1s
Acceleration = v-u /t
a= 100 - 0/ 0.1s
= 100 / 1/ 10s
= 1000 m/s²
Force ,F = ma
F = 1/20 × 1000 = 50 kgm/s²
= 50N
hope it helps you
mass of bullet = 50 g = 50 / 1000 kg = 1/20kg
Initial velocity ,ie bullet at rest in the gun
u = 0
and final velocity ,v = 100m/s
t = 0.1s
Acceleration = v-u /t
a= 100 - 0/ 0.1s
= 100 / 1/ 10s
= 1000 m/s²
Force ,F = ma
F = 1/20 × 1000 = 50 kgm/s²
= 50N
hope it helps you
Similar questions