Question

a bullet released by gun of mass 5 kg then the gun is recoil with 2 into 10 power minus 4 metre per second if mass of bullet is 0.040 then find which velocity Bullet is been released by gun​

Answer 1

Answer:mass of gun(m1)=5kg

Acceleration of gun(a1)=2×10^-4

Mass of bullet (M2))=0.040kg

Acceleration of bullet (a2)=m1×a1÷M2

=0.025m/s^2

Explanation: