Question

A bullet weighing 10 g is fired with a velocity of 800 m/s after passing through a mud hole 1m thick its velocity is 100 m/s find the average resistance offered by the mud hole

Answer 1

Initial velocity (u) = 800 m/s

Final velocity (v) = 100 m/s

Mass of bullet = 10 gram = 0.01 kg

Distance the bullet covered = 1 m

Let the acceleration given by mud be a.

$v^2 = u^2 + 2as$

$a = \frac{v^2 - u^2}{2s}$

$a = \frac{800^2 - 100^2}{2}$

a = 630000 m/s^2

Force = mass × acceleration

Force = 0.01 × 630000

Force = 6300 N

Hence, the force applied by the mud = 6300 N

Answer 2

see the attachment for the answer