Question

A bus accelerates uniformly 72 km/hr to 30 m/s in 6 hr. what is the acceleration and distance travelled by the body?
​

Answer 1

v

c

=54 km/h=

3600

54×1100

=15 m/s

v

f

=72 km/h=

3600

72×1000

=20 m/s

∴ Acceleration

t

v

f

−v

c

=

10

20−15

=0.5 m/s

2

Answer 2

Answer:

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Step-by-step explanation:

Given, the bus has started from rest.

Given, the bus has started from rest.Hence, initial velocity, u=0.

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36×

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 3600

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a=

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= t

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u =

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u = 10

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u = 1010−0

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u = 1010−0

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u = 1010−0 =1 m/s

Given, the bus has started from rest.Hence, initial velocity, u=0.Given, final velocity, v=36 kmph= 36× 36001000 m/s or, v=10 m/s Time, t=10 s∴ acceleration, a= tv−u = 1010−0 =1 m/s 2