Question

A bus accelerates uniformly from 54 km/h to 72 km /h in 10 seconds calculate (1) acceleration in m/s square (2) distance covered by the bus in meter during this interval

Answer 1

ʜᴇʟʟᴏ ᴍᴀᴛᴇ

52 ᴋᴍ/ʜ = 54 × 5 / 18
= 15 ᴍ/s

72 ᴋᴍ/ʜ = 72 × 5 / 18
= 20 ᴍ/s

(ɪ) ᴠ = ᴜ + ᴀᴛ
20 = 15 + ᴀ(10)
20 - 15 = 10ᴀ
5/10 = ᴀ ᴏʀ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ = 0.5 ᴍ/s²

(ɪɪ) ᴠ² - ᴜ² = 2ᴀs
20² - 15² = 2(0.5)s
( 20 + 15 )( 20 - 15 ) = s
35*5 = s

ʜᴇɴᴄᴇ ᴅɪsᴛᴀɴᴄᴇ ᴛʀᴀᴠᴇʟʟᴇᴅ ɪs 175 ᴍ

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