Question

A bus between kota to Jaipur passed the 100 km, 160 km, and 220 km points at 10:30am ,11:30am and 1:30pm . Find the average speed of the bus during each of the following intervals :
a) 10:30am to 11:30am
b) 11:30am to 1:30pm and
c) 10:30am to 1:30pm

plzz tell me answer guys it's urgent plzz ​

Answer 1

Hey Dear,

# Given -

s1 = 160 km - 100 km = 60 km

s2 = 220 km - 160 km = 60 km

t1 = 11.30 am - 10.30 am = 1 hr

t2 = 1.30 pm - 11.30 am = 2 hr

# Solution -

(i) During 10.30 am to 11.30 am, average speed of the the bus will be -

v1 = s1 / t1

v1 = 60 / 1

v1 = 60 km/hr

(ii) During 11.30 am to 1.30 pm, average speed of the the bus will be -

v2 = s2 / t2

v2 = 60 / 2

v2 = 30 km/hr

(iii) During 10.30 am to 1.30 pm, average speed of the the bus will be -

v = (s1+s2) / (t1+t2)

v = (60+60) / (1+2)

v = 40 km/hr

Thanks for asking..

Answer 2

Answer:

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Explanation:

Hey Dear,

# Given -

s1 = 160 km - 100 km = 60 km

s2 = 220 km - 160 km = 60 km

t1 = 11.30 am - 10.30 am = 1 hr

t2 = 1.30 pm - 11.30 am = 2 hr

# Solution -

(i) During 10.30 am to 11.30 am, average speed of the the bus will be -

v1 = s1 / t1

v1 = 60 / 1

v1 = 60 km/hr

(ii) During 11.30 am to 1.30 pm, average speed of the the bus will be -

v2 = s2 / t2

v2 = 60 / 2

v2 = 30 km/hr

(iii) During 10.30 am to 1.30 pm, average speed of the the bus will be -

v = (s1+s2) / (t1+t2)

v = (60+60) / (1+2)

v = 40 km/hr

Thanks for asking..