Question

a bus changes its velocity from 2m/s to 10m/s at a rate of 8m/s^2. How much time is required. (Explain the process also)

A.1 sec
B.2 sec
C.8 sec​

Answer 1

Answer:

A. 1SEC.

Explanation:

a=8m/s^2.

v=2m/s

u=10m/s

t=?

$a = \frac{(u - v)}{t} \\ 8 = \frac{(10 - 2)}{t} \\ \\ 8 = \frac{8}{t} \\ t = 1sec(8 \: cancel)$

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Answer 2

Answer:

1second

Explanation:

use

v equal to u+at

v means final velocity

u mean inetial velocity

a means Acceleration

t mean time so

v equal to 10

u equal to 2

a equal to 8

t equal to?

10 equal to 2+8.t

10-2 equal to 8t

8 equal to 8t

t equal to 1