a bus driver traveling with a uniform speed of 18km/hr accelerates his bus for 10 seconds. if the speed of the bus after 10th second becomes 90km/hr calculate the rate at which it accelerates.
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a=v-u/t
here v=90km/h and u=18km/h and t=10s
convert v and u into m/s
v=90×5/18=25/m
u=18×5/18=5m/s
a=25-5/10
a=20/10
a=10m/s^2
here v=90km/h and u=18km/h and t=10s
convert v and u into m/s
v=90×5/18=25/m
u=18×5/18=5m/s
a=25-5/10
a=20/10
a=10m/s^2
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