A bus is moving with a speed of 72km/h. On applying brakes, it comes to rest in 5s.Find the acceleration and the distance travelled by the bus before coming to rest.
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Answer:
-4m/s^2
Explanation:
Initial velocity(u)=72km/ hr
=72 ×5/18=20m/s
Final velocity(v)= 0
Time=5second
A=V-U
T
A= 0-20/5
= -20/5= -4
AND you can find Distance on the 2nd equation of motion
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