a bus is moving with a velocity of 72km/h on seeing red signal of traffic at 27m ahead on the road,the driver applied brake and stopped in 25m calculate the time taken
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Time taken by bus to stop = 2.5 sec if it was running at 72 km/hr and stopped after 25 m on applying brake
Explanation:
bus is moving with a velocity of 72km/h
=> bus Velocity = 72 * 1000 / 3600 m/s = 20 m/s
initial Velocity = 20 m/s
Final Velocity = 0 m/s at it stopped
Distance covered = 25 m
Using Formula
V² - U² = 2aS
=> 0 - 20² = 2a(25)
=> a = - 8 m/s²
now using
V = U + at
=> 0 = 20 + (-8)t
=> t = 20/8 sec
=> t = 2.5 Sec
Time taken by bus to stop = 2.5 sec
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