A bus moving along a straight highway with a speed of 72 km h is brought to rest within a distance of 50 m . How long does it take for the bus to stop ?
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HINT:
first- use 3rd law of UM (v square- u square=2 acceleration x displacement)
s= 50 m
v = 0
u = 72 km/h or 20 m/s
find a
then,
second step-- use the first law of UM (v = u + a x t)
add the values and find t
( hope this was helpful because providing the entire solution would not help you but solving this question by referring to the hint would help you master these kind of questions for future )
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