A bus moving along a straight line at 20 m per second undergoes an acceleration of 4 m per second square after 2 seconds if speed will be what
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Answered by
1
Hi.
Here is your answer---
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Given---
Initial Velocity(u) = 20 m/s.
Time(t) = 42 seconds.
Acceleration(a) = 4 m/s²
Let the Final Velocity be v m/s.
Using the Formula,
Acceleration = (v - u)/t
4 = (v - 20)/2
v - 20 = 4 × 2
v = 20 + 8
v = 28 m/s.
Thus, the Final Speed of the Bus after 2 seconds will be 28 m/s.
________________
Hope it helps.
Have a nice day.
Here is your answer---
__________________
Given---
Initial Velocity(u) = 20 m/s.
Time(t) = 42 seconds.
Acceleration(a) = 4 m/s²
Let the Final Velocity be v m/s.
Using the Formula,
Acceleration = (v - u)/t
4 = (v - 20)/2
v - 20 = 4 × 2
v = 20 + 8
v = 28 m/s.
Thus, the Final Speed of the Bus after 2 seconds will be 28 m/s.
________________
Hope it helps.
Have a nice day.
Answered by
1
Let v be the final speed of the bus.
Since the acceleration is constant, we can use the kinematic equation
v=u+at. v=20+4x2 = 28 m/s
Since the acceleration is constant, we can use the kinematic equation
v=u+at. v=20+4x2 = 28 m/s
fnazneen2d:
Nice answer
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