Question

A cannon fires a shell with a speed of 84m/s .when the cannon is inclined at 45° ,the horizontal distance covered is observed as630m .what is the percentage decrease in the horizontal distance observed due to air resistance

Answer 1

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Vo = 84m/s[45o]. 

Dx = Vo^2*sin(2A)/g=84^2*sin90/9.8=720 m 
with zero wind. 

(720-630)/720 * 100% = 12.5% Decrease.

Answer 2

Answer:

decrease in percentage =12.5%