Question

A bus of mass 10,000kg is moving with a velocity of 60 km/ h calculate the work done to stop this bus

Answer 1

mark it as brainliest

Answer 2

Mass of the bus is 10,000 kg

Velocity = 60 km/h = (60 x 1000) m/hr = 60,000/3600 m/s = (50/3) m/s

Now work done = change in kinetic energy

Here, initial kinetic energy (in joule)

= (1/2).m.v²

= (1/2) x 10000 x (50/3)²

= 1,388,888.889

As the bus stops finally the final velocity is zero,

thus its final kinetic energy will be also 0 [ (1/2) x 10000 x 0 = 0 ]

Therefore, net work done

= initial KE - Final KE

= 1,388,888.889 - 0

= 1,388,888.889 J