A bus runs for 3 hours at a speed of 45 km per hour and for the next 2 hours at a speed of 50 km per hour. Find the average speed of the bus for the 5 hours journey.
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Avg speed = (total distance covered)/total time
Savg = ((45x3)+(50x2))/(3+2)
= (135+100)/5
= 235/5
= 47 km/hr
Savg = ((45x3)+(50x2))/(3+2)
= (135+100)/5
= 235/5
= 47 km/hr
Robinson11:
thnks
Answered by
0
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Sol : Distance covered by bus in first 3 hours = Speed x Time
= 45 x 3 km = 135 km.
Distance covered by bus in next 2 hours = Speed x Time
= 50 x 2 km = 100 km.
Total distance covered by bus = 135 km + 100 km = 235 km.
Total time taken to cover 235 km = 5 hours.
Total distance covered by body
Average speed = -------------------------------------------
Total time taken
235 km
Average speed = -------------
5 h
Average speed = 47 km/h.
☺☺☺
Sol : Distance covered by bus in first 3 hours = Speed x Time
= 45 x 3 km = 135 km.
Distance covered by bus in next 2 hours = Speed x Time
= 50 x 2 km = 100 km.
Total distance covered by bus = 135 km + 100 km = 235 km.
Total time taken to cover 235 km = 5 hours.
Total distance covered by body
Average speed = -------------------------------------------
Total time taken
235 km
Average speed = -------------
5 h
Average speed = 47 km/h.
☺☺☺
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