Question

a bus staring from its rest moves with a uniform acceleration of 0.1 m/s for 2 mins find 1) the speed acquired 2) the distance travelled

Answer 1

here is your answer.. Here, acceleration a = 0.1 ms-2

Time t = 2min = 2 x 60 = 120s

Initial speed u = 0

(a) From Ist equation of motion, speed acquired, v = u + at

= 0 + 0.1 x 120

 = 12 ms-2

(b) From IInd equation of motion,

Distance travelled,



= 0.1 x 60 x 120 = 720 m

Answer 2

ANSWER IS HERE

$<b > <i >$

u =0

a=0.1m/
${s}^{2}$

t=2 min

2×60sec

120sec

Distance =s=ut+1/2a
${t}^{2}$

s=0×120+1/2×0.1×
${120}^{2}$
s=1/2 ×0.1×14400

s=0.1×7200

s=720

Distance =720 m

Speed =v=u+at

v =0+0.1×120

v =12 m/
${s}^{2}$

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